Question

A,b,c can do a piece of work in 150 days,75 days and 75/2 days respectively.if all three work alternatively start with a, then b followed by c, then how many days work will be completed

Answer 1

A takes 150 days to complete the work

so A's one day work = 1/150

B takes 75 days to complete the work

so B's one day work = 1/75 = 2 / 150

C takes 75/2 days to complete the work

so C's one day work = 2/75 = 4 / 150

on first day , A completes 1/150 work

on second day B adds 2/150 work

and on third day C adds 4/150 work


so after 3 days together their work is = 7/150

so 3 days -------- 7 / 150 work


30 days -------- 70 / 150 work

60 days -------- 140 / 150 work

63 days -------- 147 / 150 work

on 64 th day A adds 1/150 work

completed work becomes , 148/150

on 65 th day B adds 2/150 work

completed work becomes , 150/150


so in 65 days whole work completes

Answer 2

A takes 150 days to complete the work

so A's one day work = 1/150

B takes 75 days to complete the work

so B's one day work = 1/75 = 2 / 150

C takes 75/2 days to complete the work

so C's one day work = 2/75 = 4 / 150

on first day , A completes 1/150 work

on second day B adds 2/150 work

and on third day C adds 4/150 work

so after 3 days together their work is = 7/150

so 3 days -------- 7 / 150 work

30 days -------- 70 / 150 work

60 days -------- 140 / 150 work

63 days -------- 147 / 150 work

on 64 th day A adds 1/150 work

completed work becomes , 148/150

on 65 th day B adds 2/150 work

completed work becomes , 150/150

the answer is 65

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