a,b,c can do a piece of work in 20 ,30 and 60 days respecitvaly , if a is assisted by b and c on every third bay the work will be finish
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(A + B + C)'s work in 1 day = 1/20 + 1/30 + 1/60
= 1/10.
A's 2 days work = (1/20 * 2)
= 1/10.
Given that A is assisted on every 3rd day.
work is done in 3 days = 1/10 + 1/10
= 1/5.
Total work = 3 * 5 = 15 days.
= 1/10.
A's 2 days work = (1/20 * 2)
= 1/10.
Given that A is assisted on every 3rd day.
work is done in 3 days = 1/10 + 1/10
= 1/5.
Total work = 3 * 5 = 15 days.
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Sorry for delay on bike at that time
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