Question

A,B,C can do a piece of workin 10,12and 25 days respectively.After 3days ,B left the work. In how many days,the remaining work will be completed by both A and C together?​

Answer 1

Answer:

Per the question:

10A=1

12B=1 and

25C=1

Then:

300A=30

300B=25

300C=12

So:

300(A+B+C)=30+25+12=67

300/67(A+B+C)=1

After 3 days, the amount of work done would be:

3 x 67/300=201/300

So 99/300, or 33/100ths of the work is left. A and C, together can do:

50A=5

50C=2

50(A+C)=5+2=7

A+C=7/50ths of the work per day

Then:

33/100 / 7/50=33/100 x 50/7=33/14 days before A and C, working together, can finish the work