A b c can do a piece work 6 days if a alone complete 12 days and b alone complete 18 days how many days c alone work
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A, B and C can do a piece work 6 days.
And A alone complete 12 days and B alone complete 18 days.
(A + B + C)'s one day work = 1/6
(A + B)'s one day work = 1/12 + 1/18
= (3 + 2)/36
= 5/36
Find the time taken by C to complete the work alone :-
(A + B + C)'s one day work - (A + B)'s one day work
= 1/6 - 5/36
= (6 - 5)/36
= 1/36
C's one day work = 1/36
Hence,
C alone can do the same work in 36 days.
A, B and C can do a piece work 6 days.
And A alone complete 12 days and B alone complete 18 days.
(A + B + C)'s one day work = 1/6
(A + B)'s one day work = 1/12 + 1/18
= (3 + 2)/36
= 5/36
Find the time taken by C to complete the work alone :-
(A + B + C)'s one day work - (A + B)'s one day work
= 1/6 - 5/36
= (6 - 5)/36
= 1/36
C's one day work = 1/36
Hence,
C alone can do the same work in 36 days.
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