Math, asked by vedantnaik0005, 10 months ago

(a+b) (c-d) + (a-b) + (c+d) + 2(ac+bd)​

Answers

Answered by sidharth56
4

Answer:

(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)

now we multiply each other,

=a(c-d)+b(c-d)+a(c+d)-b(c+d)+2(ac+bd)

=ac-ad+bc-bd+ac+ad-bc-bd+2ac+2bd

=2ac-2bd+2ac+2bd

= 4ac

Answered by shivanshu122
2

Answer:

(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)

Final result :

4ac

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((a+b)•(c-d))+((a-b)•(c+d)))+2•(ac+bd)

Step 2 :

Equation at the end of step 2 :

(((a+b)•(c-d))+(a-b)•(c+d))+2•(ac+bd)

Step 3 :

Equation at the end of step 3 :

((a+b)•(c-d)+(a-b)•(c+d))+2•(ac+bd)

Step 4 :

Final result :

4ac.

plz thank and Mark as brainlist

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