Math, asked by praneeth94, 5 months ago


(a + b) (c- d) + (a - b) (c + d) + 2 (ac + bd)​

Answers

Answered by TyuzuRiki
8

(a + b) (c- d) + (a - b) (c + d) + 2 (ac + bd)

Now We Should Multiply Eachother,

= a (c-d) + b(c-d) + a(c+d) - b(c+d) +2(ac+bd)

= ac - ad + bc - bd + ac + ad - bc - bd + 2ac + 2bd

= 2ac - 2bd + 2ac + 2bd

= 4ac

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