Math, asked by greeshma8751, 15 hours ago

(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)​

Answers

Answered by mamtabrijesh
1

Answer:

HERE YOUR ANSWER

Step-by-step explanation:

(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)

now we multiply each other,

     =a(c-d)+b(c-d)+a(c+d)-b(c+d)+2(ac+bd)

         =ac-ad+bc-bd+ac+ad-bc-bd+2ac+2bd

            =2ac-2bd+2ac+2bd

                = 4ac

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