Question

(a+b) (c-d) + (a-b) (c+d) + 2 (ac+bd)​

Answer 1

Answer:

(a+b)(c−d)+(a−b)(c+d)+2(ac+bd)

=(ac+bc−ad−bd)+(ac+ad−bc−bd)+2(ac+bd)

=4ac.

Step-by-step explanation:

hope it's help u.

pls add me in brainlist

Answer 2

Step-by-step explanation:

(a+ b) (c – d) + (a – b) (c + d) + 2(ac + bd) (a + b) (c – d) + (a -b) (c + d) + 2(ac + bd) = a (c – d) + b(c – d) + a(c + d) – b(c + d) + 2 (ac + bd) = ac – ad + bc – bd + ac + ad – bc – bd + 2 ac + 2 bd = ac + ac + 2ac – ad + ad + be – bc – bd – bd – 2 bd = 4acRead more on Sarthaks.com - https://www.sarthaks.com/819948/simplify-a-b-c-d-a-b-c-d-2-ac-bd