(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)
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(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)
=ac - ad + bc - bd +(a-b)×(c+d)+2(ac+bd)
=ac-ad+bc-bd+ac+ad-bc-bd +2(ac +bd)
=ac-ad+bc-bd+ac+ad-bc-bd +2ac+2bd
= 4ac- bd - bd +2bd
=4ac + 0
=4ac is your answer
memustafabanday:
Why u didn't multiply a-b
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1
4ac is the answer.......
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