(a+b)(c+d)+(a-b)(c+d)+2(bc+ab) =????
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Answer:⬇️⬇️
(a+b)(c-d)+(a-b)(c+d)+2(ac+bd)
now we multiply each other,
=a(c-d)+b(c-d)+a(c+d)-b(c+d)+2(ac+bd)
=ac-ad+bc-bd+ac+ad-bc-bd+2ac+2bd
=2ac-2bd+2ac+2bd
= 4ac
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