Question

a/b+c/d = a+c/b+d
$\frac{a}{b} + \frac{c}{d} = \frac{a + c}{b + d}$
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Answer 1

THE ANSWER FOR YOUR QUESTION IS :

$a = - \frac{cb ^{2} }{d ^{2} }$

NOW LETS SEE THE STEPS FOR SOLVING :

$\frac{a}{b} + \frac{c}{d} = \frac{a + c}{b + d}$

$d(b + d)a + b(b + d)c = bd(a + c)$

$(db + d ^{2} )a + b(b + d)c = bd(a + c)$

$dba + d ^{2} a + b(b + d)c = bd(a + c)$

$dba + d ^{2} a + (b ^{2} + bd)c = bd(a + c)$

$dba + d ^{2} a + b ^{2} c + bdc = bd(a + c)$

$dba + d ^{2} a + b ^{2} c + bdc = bda + bdc$

$dba + d ^{2} a + b ^{2} c + bdc - bda = bdc$

$d ^{2} a + b ^{2}c + bdc = bdc$

$d ^{2} a + bdc = bdc - b ^{2} c$

$d ^{2} a = bdc - b ^{2} c - bdc$

$d ^{2} a = - b ^{2}c$

$d ^{2} a = - cb ^{2}$

$\frac{d ^{2} a}{d ^{2} } = - \frac{cb ^{2} }{d ^{2} }$

$a = - \frac{cb ^{2} }{d ^{2} }$

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