Math, asked by satyabratnayak96, 3 months ago

A,B,C,D & E there are five friends .the average age of A,B &C was 50 year. if five years ago the age of D is 75 year & the present average age of A,B,C,D &E is 60 year.what is the age of E ?​

Answers

Answered by prasanthikuchipudi
0

Answer:

E=80 years

Step-by-step explanation:

the average age of A,B &C was 50 year

(A+B+C)/3=50

A+B+C=50*3

A+B+C=150

if five years ago the age of D is 75 year

Present age of D is 75-5=70

the present average age of A,B,C,D &E is 60 year

(A+B+C+D+E)/5=60

A+B+C+D+E=60*5

A+B+C+D+E=300

we know D and A+B+C values

150+70+E=300

E=80

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