Question

a, b, c, d are four consecutive perfect square. What is the number of odd numbers of between a and d?​

Answer 1

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$\sqrt{a} + \sqrt{b} + \sqrt{c} + 1$

$\fbox{\fbox{\large{\bold{Solution:-}}}}$

Number whole numbers between two consecutive perfect squares m and n is 2$\sqrt{m}$ in that half of the numbers are odd and the rest are even.

So numbers of odd number

$= > \sqrt{m}$

So in the given problem between perfect squares a and d, there will be

$\sqrt{a} + \sqrt{b} + \sqrt{c}$

non - perfect odd number squares

Between a and d, either b and c will be odd.

So the total number of odd numbers between a and d is

$\sqrt{a} + \sqrt{b} + \sqrt{c} + 1.$

Answer 2

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$\sqrt{a} + \sqrt{b} + \sqrt{c} + 1$

Refer to the attachment.