Question

A, B, C, D are four point on circle AC and interst at points E such that √ BEC= 130° √ ECD =20° √BAC​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

∠BEC+∠DEC=180  

∘

 (complimentary angles)  

130  

∘

+∠DEC=180  

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∠DEC=50  

∘

 

In ΔDEC -  

∠DEC+∠ECD+∠CDE=180  

∘

 

∠CDE=110  

∘

 

by theorem of circles -

∠BAC=∠CDE

∴∠BAC=110  

∘