Question

A, B, C, D are successive vertices of a cyclic quadrilateral. prove that tan(a+b) + tan(c+d) =0​

Answer 1

Answer:

I'm using quadrilateral concept

Sum of all angles of a quadrilateral is 360

A+B+C+D = 360

Thus C+D = 360-(A+B)

tan(C+D) = tan (360-(A+B))

tan (360 - theta) = -tan theta

So tan(A+B) + tan(C+D) = tan(A+B) - tan(A+B) = 0

Answer 2

Answer:

answer is 0

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Step-by-step explanation:

Explanation is given in the pic attached

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