A,B,C,D are the points on the
Circle with centre o angleADb = 50°
find
a. Angle acb
b. Angle sob
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Answer:-
angle ACB=65° ✓
Explanation:
AOBD is a quadrilateral
sum of angles of quadrilateral=360°
☞ angle BOA +90°+ angle ABD+90°=360°
☞angle BOA+50°=180°
☞angle BOA=130°
now,
☞angle BOA = 2 angle ACB ( angle subtended by chord AB at centre and arc segment)
☞130°=2 angle ACB
therefore, angle ACB= 65°
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