Math, asked by manassrikar, 10 months ago

A,B,C,D BE the angles of quadrilateral then tanA +tanB +tanC+tanD/cotA +cotB+cotC+-cotD=?​

Answers

Answered by atikshghuge
2

Answer:

A + B = 2π – (C + D)  tan(A + B) = – tan(C + D) (tanA + tanB)/(1 - tanA tanB) = (- tanC - tanD)/(1 - tanC tanD) tanA – tanA tan C tan D + tan B – tan B tan C tan D = – tanC + tan A tan B tan C – tan D + tan A tan B tan D  tan A + tan B + tan C + tan D = tan A tan C tan D + tan B tan C tan D + tan A tan B tan C + tan A tan B tan D = tan A tan B tan C tan D (cot A + cot B + cot C + cot D) ∴ = tan A tan B tan C tan D./if-a-are-the-angles-of-quadrilateral-then-tana-tanb-tanc-tand-cota-cotb-cotc-cotd-is-equal-to

Step-by-step explanation:

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