A,B,C,D BE the angles of quadrilateral then tanA +tanB +tanC+tanD/cotA +cotB+cotC+-cotD=?
Answers
Answered by
2
Answer:
A + B = 2π – (C + D) tan(A + B) = – tan(C + D) (tanA + tanB)/(1 - tanA tanB) = (- tanC - tanD)/(1 - tanC tanD) tanA – tanA tan C tan D + tan B – tan B tan C tan D = – tanC + tan A tan B tan C – tan D + tan A tan B tan D tan A + tan B + tan C + tan D = tan A tan C tan D + tan B tan C tan D + tan A tan B tan C + tan A tan B tan D = tan A tan B tan C tan D (cot A + cot B + cot C + cot D) ∴ = tan A tan B tan C tan D./if-a-are-the-angles-of-quadrilateral-then-tana-tanb-tanc-tand-cota-cotb-cotc-cotd-is-equal-to
Step-by-step explanation:
Similar questions