Question

a + b + c + d = d+ e +f+ g = g + h + i = 17. Each of the alphabets denotes distinct natural
numbers from 1 to 9. Find value of d + g.
(A) 8
(B) 6
(C) 11
(D) 10

please answer and explain it and if you know then answer please​

Answer 1

Answer:

Option B) 6

Value Of D and G are 1 and 5.

Explanation:

A+B+C+D = 17

D+E+F+G = 17

G+H+I = 17

Adding the three equations we get,

A+B+C+2D+E+F+2G+H+I = 51

Now, we know each letter takes one digit from 1 to 9, so we can replace them with all digits from 1 to 9 i.e.

D+G+1+2+3+4+5+6+7+8+9 = 51 or D+G+45 = 51

therefore,

D+G = 6

So, possible value pairs for D and G are

1,5 (possible)

2,4 (not possible as we know A = 4)

3,3(not possible as each digit is assigned to only one letter)

4,2(not possible as we know A = 4)

5,1 (possible)

Hence, values of D and G are 1 and 5.

Answer 2

Explanation:

hence d and g are 1 and 5 .