Question

A, B, C, D, E & F are sitting in a row facing
North. A is neighbour of B and D. E is neighbour
of C and F. D is neighbour of C. How many
members are there between A and E?
(A) Two
(B) One
(C) Three
(D) Four
(E) None of these.
​

Answer 1

Answer: (A) TWO

The sequence is BADCEF.

Answer 2

Answer:-

$\red{\bigstar}$ Number of members between A and E

$\large\leadsto\boxed{\rm\purple{Option.A \rightarrow Two}}$

• Given:-

A, B, C, D, E & F are sitting in a row facing North.

A is neighbour of B and D.

E is neighbour of C and F.

D is neighbour of C.

• To Find:-

Number of members are there between A and E

• Solution:-

Looking at:-

★ 1st condition:-

$\underline{\pink{\bf Statement}}$:: A is neighbour of B and D.

Now, A can only be the neighbour of B and D when A is in between B and D.

Hence, we can say that A is sitting between B and D.

★ 2nd condition:-

$\underline{\pink{\bf Statement}}$:: E is neighbour of of C and F.

We can say that E is sitting in between C and F as he is the neighbour of both C and F.

★ 3rd condition:-

$\underline{\pink{\bf Statement}}$:: D is neighbour of of C

When D is the neighbour of C we can conclude the order of sitting arrangment using above 2 statements.

The arrangement will be such as:-

$\underline{\boxed{\green{\bf B,A,D,C,E,F}}}$

The above arrangement fulfills the given conditions.

Now, we have to find out the number of members between A and E.

We can clearly see that D and C are sitting in between A and E.

Therefore, the number of members between A and E are Two.