Question

A, B, C, D, E and F are the points such that no three points are collinear. How many segments can be drawn by joining the pairs of these points ? (1) 13 (2) 14 (3) 15 (4) 16​

Answer 1

Answer:

There are total 15 line segments will be formed

Step-by-step explanation:

Suppose A B C D E and F are the points that no three points are colinear( in same straight line )

So line segment which is formed by any two points

iF we take Point A than line segment will be formed as AB AC AD AE AF that means 5 from point A.

Similarly from Point B there will be 4 As

BC BD BE BF

similarly from C D E F will form 3 2 1 respectively So the total line segment will be formed

5+4+3+2+1=15

So the correct answer is 15 ✓✓✓