A,b,c,d,e are five consecutive even numbers. If the sum ot a and d is 162. What is the sum of all the numbers
Answers
Answered by
6
Hi ,
Let a = x ,
b = x+2,
c = x+4,
d = x+6,
e= x+8
are five consecutive even numbers.
according to the problem given,
a + e = 162
=> x + x + 8 = 162
=> 2x = 162 - 8
=> x = 154/2
x = 77
Therefore ,
sum of all the numbers
= a + b + c + d + e
= x+x+2+x+4+x+6+x+8
= 5x + 20
= 5 × 77 + 20
= 385 + 20
= 405
I hope this helps you.
: )
Let a = x ,
b = x+2,
c = x+4,
d = x+6,
e= x+8
are five consecutive even numbers.
according to the problem given,
a + e = 162
=> x + x + 8 = 162
=> 2x = 162 - 8
=> x = 154/2
x = 77
Therefore ,
sum of all the numbers
= a + b + c + d + e
= x+x+2+x+4+x+6+x+8
= 5x + 20
= 5 × 77 + 20
= 385 + 20
= 405
I hope this helps you.
: )
Answered by
1
let the 5 consecutive even numbers be
x , x+2 , x+4 , x+6 , x+8
a b c d e
i ve written the consecutive series as x ,x+2 and so on becuase they are even consecutive intergers.
Suppose we take first number be 2 then the seccond number would be 4 and 6 and 8 and so on......increasing by 2
According to question
x + (x+6) = 162
2x + 6= 162
2x = 156
x = 78
So our series will be
78 , 80 , 82 , 84 , 86
and our sum will be 78+80+82+84+86 = 410
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