Math, asked by Honey9927, 1 year ago

a,b,c,d,e are in a.p then find the value of a-4b+6c-4d+e

Answers

Answered by SravyaMaddula

u can take any one of the two as answer

Attachments:

Honey9927: options are 0,1,2, none of these

SravyaMaddula: hoo k wait

SravyaMaddula: ans is 0

Honey9927: thank u

SravyaMaddula: u r welcome

Honey9927: plz tell thus one also.....if The sum of n terms of an a.p is 4n (n-1).then find the sum of their squares

SravyaMaddula: what are the options

Honey9927: n raised to the power 3;32/3×n (n-1)(2n-1);16/3×n (n-1)(2n-1);4n (n-1)(2n-1)

Answered by BEJOICE

Since a,b,c,d,e are in AP,
2b = a+c and 2d = c+e

Substituting in given expression,
a-4b+6c-4d+e = a -2a-2c + 6ç -2c-2e +e
= 2c - (a+e) = 0

Note: 2c = b+d = a+e since they are in AP

Honey9927: can't you give me the whole sol

Honey9927: plz give me whole solution

BEJOICE: It's very difficult to type mathematical expression in the chat

Honey9927: solve on a paper

BEJOICE: Give your email ID, i will send full solution

BEJOICE: Solved on paper already

BEJOICE: how to attach in the chat

Honey9927: i don't have any id

Honey9927: like others have attached

Honey9927: how does (n-1)(2n-1) will come

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