A, B, C, D, E are the points on the circle. O is the centre angle ADE =30⁰ angle ABC=130 ⁰ calculate angle ACE ,angle AEC and angle EOC.
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Step-by-step explanation:
, < ABC + < AEC = 180° ( opposite angles of cyclic quadrilateral)
But < ABC = 130°
=> < AEC = 50° …………. (1)
Similarly < CDE + < CAE = 180° ( same reason)
But < CDE = 110°
=> < CAE = 70° ………. (2)
Now, in triangle ACE
< AEC + < CAE + < ACE = 180° ( angle sum property)
=> 50° + 70° + < ACE = 180°
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