Question

A B C D E F are the points such that no three points are collinear how many segments can be drawn by joining the pairs of these points​

Answer 1

There can be 15 different segments.

Step-by-step explanation:

There are six points with names A, B, C, D, E, and F such that no three points are collinear.

Then we have to find out the number of segments that can be formed by joining the pairs of these points.

If we joint point A with the other points, then there will be 5 distinct segments with names AB, AC, AD, AE, and AF.

Similarly, if we join point B with other points except A (because segment AB and segment BA are the same), then there will be four distinct segments with names BC, BD, BE, and BF.

In this way the total number of distinct segment that can be formed with pair of points will be (5 + 4 + 3 + 2 + 1) = 15. (Answer)

Answer 2

Step-by-step explanation:

Answer is (3) 15

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