Question

A b c d e f g are consecutive even numbers and j k l m n are consecutive odd numbers the average of all numbers is

Answer 1

Solution:

Given A ,b,c,d,e,f,g are consecutive even Numbers

A ,

b = A+2,

c = A+4,

d = A+6,

e = A+8,

f = A +10,

g = A + 12

and

j,k,l,m,n are consecutive odd numbers

j

k = j + 2,

l = j + 4,

m = j+6,

n = j+8

Now ,

Average of all numbers

= [(A+A+2+A+4+A+6+A+8+A+10+A+12)+(j+j+2+j+4+j+6+j+8)]/12

= (7A+42+5j+20)/12

= (7A+5j+62)/12

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