Question

A B
-
C D
F - G H -
E
I -
Second beriod.
Third period
Assumed that E is second last element of I
beriod of mp.t. of value of so is for F is
yo then value of sigma for H should be​

Answer 1

ANSWER:

1. Second last element of third period is chlorine with atomic number 17.

2. Second period contains 8 elements from Li to Ne

3. Chlorine has highest electron affinity.

4. Flourine has highest electro negativity.

5. Group I is the Alkali metals . So the element is Hydrogen which is placed in Group 1 and period 1 but it is not included as Alkali metal.

Answer 2

Answer:

I don't know

Explanation:

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