Question

A+B=C + D If initially of A and B are both are taken in equal amount but at equilibrium concentration
of D will be twice of that of A then what will be the equilibrium constant of reaction :-
A. 4/9 b 9/4 C 1/9 d. 4​

Answer 1

Answer:

d

Explanation:

aA + bB = cC + dD

Since it is given conc. of A and B are equal,

if take conc. of A=1 and D=2

K=(c+2)/(1+1)

K=(c+2)/2

So according to the options,

the answer cannot be A since c will be always be positive, so the numerator will be bigger than denominator.

b cannot be the answer since simplified version of b cannot give denominator as 2 in a fraction.

c cannot be the answer due to same reason as the first one.

So the answer can only be the last one.