A B C D is a
trapezium
AB//CD, AE=ED, EF// AB // CD
Prove- 1) F is midpoint of BC
2)EF =½(AB+CD)
Answers
Answered by
0
Step-by-step explanation:
1.AE=ED
BF=FC
F is midpoint of BC
Answered by
3
Answer:
we can solve it by mid point theorem
Step-by-step explanation:
AE=ED is given. That means E is the midpoint of AD.
Construction: Join AC.
Proof: In ∆ADC,
AE=ED
EO||DC
:. By converse of mid point theorem, O is the midpoint of AC.
Also EO=1/2 DC...........(1)
In ∆BAC,
AO=OC
OF||AB
:. By converse of mid point theorem, F is the midpoint of BC [(i) is proved]
Also OF=1/2 AB.............(2)
Adding (1) and (2), we get
EO+OF=1/2 DC+ 1/2 AB
EF=1/2(AB+DC) [(ii) is proved]
#together_we_go_far❤️
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