A+B+C+D+Z+Y=______________
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Answered by
3
Answer:
It is given that A={x,y,z} and B={1,2}
∴ A×B={(x,1),(x,2),(y,1),(y,2),(z,1),(z,2)}
Since n(A×B)=6
The number of subsets of A×B is 26.
Answered by
3
Answer:
A=1
B=2
C=3
D=4
Z=26
Y=25
A+B+C+D+Z+Y=1+2+3+4+26+25=61
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