a+b+c (ii) 1/a+1/b+1/c (iii) a²+b²+c².
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Step-by-step explanation:
(1−a)(1−c−b+bc)
=1−c−b+bc−a+ac+ab
=1−(a+b+c)+(ab+bc+ac)
=1−1+ab+bc+ac
=
2
2(ab+bc+ac)
=
2
(a+b+c)
2
−(a
2
+b
2
+c
2
)
=
2
1−21
=−10
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