A B C is an isosceles triangle with AB = AC. Draw AP BC to show that angle B = angle C
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Step-by-step explanation:
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Solution:
In △ABP and △ACP
AB=AC (Given)
∠APB=∠APC (Each equal to 90°)
AP=AP (Common)
Therefore, by RHS congruence rule, △ABP≅△ACP
Hence, ∠B=∠C (Corresponding parts of congruent triangles are equal)
hope, this will help you.
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