Question

a + b + C is equal to 6 and a square + b square + c square is equal to 20 find the value of AB + BC + CA ​

Answer 1

Answer:

ab + bc + ca = 8

Step-by-step explanation:

   a + b + c = 6

a² + b² + c² = 20

Using the formula,

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Substituting the values,

6² = 20 + 2(ab + bc + ca)

∴ 36 - 20 = 2(ab + bc + ca)    

     16 ÷ 2 = ab + bc + ca

∴ ab + bc + ca = 8.

Answer 2

Answer:

(A+B+C)^2=36

36=A^2 + B^2 +C^2 + 2AB + 2BC +2CA

36=20 + 2(AB + BC + CA)

16=2(AB + BC +CA)

AB + BC +CA = 8

Step-by-step explanation:

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