Question

a + b + c is equals to 9 and a b + BC + CA is equal to 26 find the value of a square + b square + c square​

Answer 1

hi mate your answer↓

ab+bc+ac=26

multiplying by 2

2ab+2bc+2ac=52

a^2+b^2+c^2=(a+b+c)^2-(2ab+2bc+2ac)

=9^2-52

=81-52

=29

hope that it will help you

Answer 2

Answer:

29

Step-by-step explanation:

a + b + c = 9

ab + bc + ca = 26

a² + b² + c² = ?

We know that,    (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

Thus,

   (9)² = [a²+ b² + c²] + 2(26)

   81 = (a² + b² + c²) + 52

⇒ a² + b² + c² = 81 - 52 = 29

Hence, the answer is 29.