Question

(a+b+c) raised to 2
Please answer my qiestion​

Answer 1

Answer:

a2+b2+c2+2ab+2bc+2ca

Step-by-step explanation:

PROOF:-

(a+b+c)2  can be written as  (a+b+c)∗(a+b+c) ,

Therefore,  (a+b+c)2=(a+b+c)∗(a+b+c)  

=a(a+b+c)+b(a+b+c)+c(a+b+c)  

=a2+ab+ca+ab+b2+bc+ca+bc+c2  

=a2+b2+c2+ab+ab+bc+bc+ca+ca  

=a2+b2+c2+2ab+2bc+2ca  

Thanks for Reading!

Answer 2

Step-by-step explanation:

a2+b2+c2+2ab+2bc+2ca