A+B+C = π then prove that A=B=C
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a+b+c=π
a+b=π-c
∴ a/2 + b/2 = π/2 - c/2
sin(a/2+b/2) = sin(π/2-c/2) = cos c/2
cos(a/2+b/2) = cos(π/2-c/2) = sin c/2
L:H:S = sin a + sin b + sin c
= 2sin(a/2+b/2).cos(a/2-b/2) + 2sin c/2.cos c/2
= 2cos c/2.cos(a/2-b/2) + 2sin c/2.cos c/2
= 2cos c/2 [cos(a/2-b/2) + sin c/2]
= 2cos c/2 [cos(a/2-b/2) + cos(a/2+b/2)
= 2cos c/2 * 2cosa/2.cosb/2
= 4cos a/2.cos b/2.cos c/2
= R:H:S
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