Math, asked by harshbhardwaj64, 1 year ago

A+B+C=π thrn tanA+tanB+tanC/tanA*tanB*tanC =

Answers

Answered by amigo3
1
A+B+C=π
therefore: A+B+C=180
A+B=180-C
Apply tan on both sides:
tan(A+B)=tan(180-C)
tanA+tanB/1-tanAtanB=-tanC
tanA+tanB=-tanC+tanAtanBtanC
tanA+tanB+tanC/tanAtanBtanC=1

Hope this helps
CHEERS!!!
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