Question

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a, b,c together does one work in 12 days. a does works twice of b. c does 1/3 work of a and b. So, in how many days C will complete the work alone. ​

Answer 1

Answer:

Let the total work be W.

Now, A,B and C together finish the work in 12 days.

Therefore, the total work done by them in one day = W/12

Let the work done by A in one day be a.

So, work done by B in one day = a/2

and that done by C in one day = (a+a/2)/3

= a/3 + a/6

= a/2

So, W/12 = a/2 + a + a/2

W/12 = 2a

a = W/24

So, work done by C in one day = a/2 = W/48

Therefore,