A, b, c, travel a distance of 1200 km Delhi to Mumbai B and C takes a car and a starts from tonga and after a certain distance b takes a cycle and c returns to takes a and finally they reach Mumbai at the same time if the speed of car is 50 kilometre per hour and the speed of cycle and tonga 10 kilometre per hour each find the total time of journey
Answers
Answer:
44.21 hrs
Step-by-step explanation:
Speed of car = 50 km/hr
Speed of Tonga & Cycle = 10 km/hr
Let say after 1200x km b takes a cycle so for 1200x km he travels with car & for remaining (1200-1200x) he travels with cycle
then total time taken by b
= 1200x/50 + (1200-1200x)/10
= 24x + 120 - 120x
= 120 - 96x hrs
Time taken to reach that point = 1200x/50 = 24x hrs
Distance traveled by a in 24x hrs = 10*24x = 240x km
While distance traveled by c in 24x hrs = 1200x km
Distance between a & c = 1200x -240x = 960x km
in next t hrs c meet a
10t + 50t = 960x
=> 60t = 960x
=> t = 16x hrs
Distance covered by a in 16x hrs = 10 * 16x = 160x
the point is 240x + 160x = 400x km
time taken = 24x + 16x = 40x
Remaining distance = 1200 - 400x = 800x
remaining distance covered by car
800x/50 = 16x
so total time taken = 40x + 16x = 56x
120 - 96x = 56x
=> 120 = 152x
=> x = 120/152
total time taken = 56x = 56 * 120/152 = 44.21 hrs
Answer:
48 hrs.........................
