Question

A,B,C walk 1 km. in 5 min., 8 min and 10 min
respectively.C start walking from a point at a
certain time B starts from the same point 2
min. later than C. Then A meets B and C at
times-

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Answer 1

Answer:

Step-by-step explanation:

Answer 2

A meets B & C  after  5/3  & 2 Mins

Step-by-step explanation:

Complete Question

A, B, C walk 1 km in 5 minute 8 minutes and 10 minute respectively, C starts walking from a point, at a certain time, B starts from the same point 1 minutes later and A starts from the same point 2 minutes later then C. then A meets B and C after.

A start 2 mins later than C

B start 1 mins Later than C

=> A start 1 min Later than B

Let say A meets B after t mins

Distance covered by A in t mins  = Distance Covered by B in t + 1 mins

=> t * /5  = (t + 1)/8

=> 8t = 5t + 5

=> 3t = 5

=> t = 5/3

Let say A meets C after t mins

Distance covered by A in t mins  = Distance Covered by C in t + 2 mins

=> t * /5  = (t + 2)/10

=> 2t = t + 2

=> t = 2

A meets B & C  after  5/3  & 2 Mins

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