a,b,c walk 1km in 5 min,8min and 10min respectively.c starts walking from a point,at a certain time,b starts from the same point 1 min later and a starts from the same point 2 min later than c.then a meets b and c after.?
Answers
Answered by
0
120 sec....
Please mark as brainliest..
Answered by
0
A meets B & C after 5/3 & 2 Mins respectively
Step-by-step explanation:
A start 2 mins later than C
B start 1 mins Later than C
=> A start 1 min Later than B
Let say A meets B after t mins
Distance covered by A in t mins = Distance Covered by B in t + 1 mins
=> t * /5 = (t + 1)/8
=> 8t = 5t + 5
=> 3t = 5
=> t = 5/3
Let say A meets C after t mins
Distance covered by A in t mins = Distance Covered by C in t + 2 mins
=> t * /5 = (t + 2)/10
=> 2t = t + 2
=> t = 2
A meets B & C after 5/3 & 2 Mins
Learn more:
Saroj, Hari and Shyam started their journey form city A to city B at the ...
https://brainly.in/question/12110382
three man goes morning walk Daily and walk to 4 kilometre 6 km 10 ...
https://brainly.in/question/11597539
Similar questions