A,B,C walk 1Km in 5 minutes, 8 minutes and 10 minutes respectively. C starts walking from a point, at a certain time, B starts from the same point 1 minute later and A starts from the same point 2 minutes later than c. Then A meets B and C at times.
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A meets B & C after 5/3 & 2 Mins
Step-by-step explanation:
A start 2 mins later than C
B start 1 mins Later than C
=> A start 1 min Later than B
Let say A meets B after t mins
Distance covered by A in t mins = Distance Covered by B in t + 1 mins
=> t * /5 = (t + 1)/8
=> 8t = 5t + 5
=> 3t = 5
=> t = 5/3
Let say A meets C after t mins
Distance covered by A in t mins = Distance Covered by C in t + 2 mins
=> t * /5 = (t + 2)/10
=> 2t = t + 2
=> t = 2
A meets B & C after 5/3 & 2 Mins
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