Math, asked by bbhawana2215, 1 year ago

a+b-c whole sqare identity

Answers

Answered by adityasi
0

Answer

(A+B-C)² = A²+B²+C²+2AB-2BC-2CA

Answered by smileplease55
0

Answer:

Answer:

(A+B-C)² = A²+B²+C²+2AB-2BC-2CA

Explanation:

We know the algebraic identity:

\boxed {(x+y+z)^{2}//=x^{2}+y^{2}+z^{2}+2xy+2yz+2zx}(x+y+z)2//=x2+y2+z2+2xy+2yz+2zx

Now ,Here

x = A , y = B, z = -C

(A+B-C)²

[A+B+(-C)]²

= A²+B²+(-C)²+2AB+2B(-C)+2(-C)A

= A²+B²+C²+2AB-2BC-2CA

Therefore,

(A+B-C)²

=A²+B²+C²+2AB-2BC-2CA

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