a+b-c whole sqare identity
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Answer
(A+B-C)² = A²+B²+C²+2AB-2BC-2CA
Answered by
0
Answer:
Answer:
(A+B-C)² = A²+B²+C²+2AB-2BC-2CA
Explanation:
We know the algebraic identity:
\boxed {(x+y+z)^{2}//=x^{2}+y^{2}+z^{2}+2xy+2yz+2zx}(x+y+z)2//=x2+y2+z2+2xy+2yz+2zx
Now ,Here
x = A , y = B, z = -C
(A+B-C)²
[A+B+(-C)]²
= A²+B²+(-C)²+2AB+2B(-C)+2(-C)A
= A²+B²+C²+2AB-2BC-2CA
Therefore,
(A+B-C)²
=A²+B²+C²+2AB-2BC-2CA
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