Math, asked by ronakgaur200, 10 months ago

A+B can complete a work in 30 day, B+C can 24 day, C+A can 20 day. Three of them start the work together but B and C left the work after 10 days and the rest of the work was completed by A. if they received rs 1200 at total wages. find out their individual share? Please solve

Answers

Answered by ritikraj200490
0

Answer:

Step-by-step explanation:

Let the number of days taken by A, B & C to complete the work individually be a, b & c respectively.

Given, A and B can do a piece of work in 30 days

=> 1/a + 1/b = 1/30

Given, B and C can do the same work 24 days

=> 1/b + 1/c = 1/24

Given, A and C can do the same work in 20 days

=> 1/c + 1/a = 1/20

Adding all the three equations,

=> 2(1/a +1/b + 1/c) = 1/30 + 1/24 + 1/20 = (20+25+30)/600 = 75/600 = 1/8

=> 1/a + 1/b + 1/c = 1/16

=> When A, B & C work together, the amount of work done in one day is 1/16

(1/a + 1/b + 1/c) - (1/b + 1/c) = 1/16 - 1/24 = (3–2)/48 = 1/48

=> 1/a = 1/48

=> The work done by A individually in one day = 1/48

Given that A, B & C work together for 10 days,

=> Work done by them together for 10 days = 10 * (1/16) = 10/16 = 5/8

=> The remaining work to be done by A alone = 1–5/8 = 3/8

The number of days taken by A alone to complete the remaining work = (3/8)/(1/48) = 18 days

Answered by TheLostMonk
1

Answer:

700,150,350

Step-by-step explanation:

T. W = LCM(30,24,20) = 120 units

their efficiencies:

A+B => 4 units/d ,B+C = 5 u/d ,C+A = 6 u/d

A+B+C = 7.5 u/d , A = 2.5 u/d ,B = 1.5 u/d

& C = 3.5 u/d

B does=1.5×10 = 15 units,C does =3.5×10=35 units

A does = 120-(15+35) = 70units

their work/shares ratio = 70:15:35 = 14 : 3 : 7

their shares

A = 14/24*1 200 = Rs 700, B = 3/24*1200

=Rs 150 & C's share= 7/24*1200 = Rs 350

Similar questions