Question

A B Cand D are four blocks of masses 3 kg, mi ms and 2 kg are suspended with light string and move in downward direction with acceleration when force of 80 N applied in upward direction on block 3 kg. If the ratio of m and ma la 2: 5, then the value of 71:79: To is ​

Answer 1

Answer:

The correct option is C

Let all the three blocks as a system.

Then f=ma

a=

M

f

Where M+m

1

+m

2

+m

3

a=

2+4+6

120

=10m/s

2

So, This is the common acceleration of all three blocks.

Since,

We have,

f−t

2

=6×10

t

2

=120−60=60N

t

2

−t

1

=4×10

t−1=60−40=20N

Thus the ratio of t

2

with t

1

is

t

2

t

1

=

60

20

1:3

Explanation:

hope this will help you