Question

A
B
С
In A ABC, ſi cot = +r2 cot = +r3 cot
2
2
2
otom​

Answer 1

Answer:

To prove: r

1

cot

2

A

=r

2

cot

2

B

=r

3

cot

2

C

=s

We know, r

1

=

s−a

S

,r

2

=

s−b

S

,r

2

=

s−c

S

Also, cot

2

A

=

(s−b)(s−c)

s(s−a)

;cot

2

B

=

(s−a)(s−c)

s(s−b)

;cot

2

C

=

(s−a)(s−b)

s(s−c)

Now,

r

1

cot

2

A

=

(s−a)

S

(s−b)(s−c)

s(s−a)

=

(s−a)

s(s−a)(s−b)(s−c)

(s−b)(s−c)

s(s−a)

=s

Similarly, r

2

cot

2

B

=s and r

3

cot

2

C

Step-by-step explanation:

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Answer 2

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