Question

A+B <=> C + D . If finally the concentration of A and B are both equal but at equilibrium concentration of D will be twice of that of a then what will be the equilibrium constant of reaction??​

Answer 1

Answer: A and B are both equal but at equilibrium, concentration of D will be twice of that of A, then the equilibrium constant of the reaction will be 4.

A+B⇌C+D

Initial concentration (M) t=0 a a 0 0

Equilibrium concentration (M) t

eq.

​

a−x a−x x x

At equilibrium, concentration of D will be twice of that of A.

x=2(a−x)

x=2a−2x

3x=2a

x=

3

2

​

a

The equilibrium constant

K=

[A][B]

[C][D]

​

K=

(a−x)(a−x)

x×x

​

K=

(a−

3

2

​

a)(a−

3

2

​

a)

3

2

​

a×

3

2

​

a

​

K=

(

9

1

​

a

2

)

9

4

​

a

2

​

K=4

Explanation: