Question

(a + b)(p + q + r)+(b + c)p +q + r) + (c + a)(p +q + r)​

Answer 1

Answer:

Step-by-step explanation:

( a + b ) ( p + q + r ) + ( b + c ) ( p + q + r ) + ( c + a ) ( p + q + r )

= ( p + q + r ) ( a + b + b + c + c + a )

= ( p + q + r ) ( 2a + 2b + 2c )

= 2 ( p + q + r ) ( a + b + c ) is the answer.

Answer 2

$\rm{Solution}:-$

$\rm{(a + b)(p + q + r) + (b + c)(p + q +r) + (c + a)(p + q + r)}$

$\rm{ \implies({ \cancel{a} + { \cancel{b}})({ \cancel{p}} + q + r)+({ \cancel{b }}+ { \cancel{c}})({ \cancel{p}} +{ \cancel{q }}+ { \cancel{r}}) + ({ \cancel{c }}+{ \cancel{ a}})(p+{ \cancel{q}} +{ \cancel{ r}})}}$

$\rm{ \implies}q + r + p$