A+B=pai/4,then (tan A+1)(tan B+1) =
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A+B=pi/4
apply tan on both sides
tan(A+B)=tan pi/4
tanA+TanB/1-tanAtanB=1
tan A + tanB=1-tanAtanB
tanA +tan B+tan A tanB=1. let this be equation 1
now,
(1+tanA)(1+tan B)=1+tanA+tanB+tanAtanB
=1+1(from eq 1)
=2
I hope u will understand.....
mark as brainliest if it helps u....
apply tan on both sides
tan(A+B)=tan pi/4
tanA+TanB/1-tanAtanB=1
tan A + tanB=1-tanAtanB
tanA +tan B+tan A tanB=1. let this be equation 1
now,
(1+tanA)(1+tan B)=1+tanA+tanB+tanAtanB
=1+1(from eq 1)
=2
I hope u will understand.....
mark as brainliest if it helps u....
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