Question

a+b power of 1/3 find the rf​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Please cross check the given statement should be:

a power 1/3 + b power 1/3 + c power 1/3 = 0

Now, let a power 1/3 = x, b power 1/3 = y, c power 1/3 = z

So, x+y+z=0

Using the identity, we get,

x power 3 + y power 3 + z power 3 = 3xyz

This gives,

(a power 1/3) power 3 + (b power 1/3) power 3 + (c power 1/3) power 3 = 3(a power 1/3) (b power 1/3) (c power 1/3)

a + b + c = 3(a power 1/3) (b power 1/3) (c power 1/3)

Cubing both sides, we get,

(a + b + c)3 = 27abc