Question

( A-B) U A = A solve using properties of sets

Answer 1

Answer:

As we know thatA−B=A∩B

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C)

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C ′

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C ′ )=(A∩B

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C ′ )=(A∩B ′

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C ′ )=(A∩B ′ )∪(A∩C

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C ′ )=(A∩B ′ )∪(A∩C ′

And also (A∩B) =A ′ ∪B ′ ,A∩(B∪C)=(A∩B)∪(A∩C)A−(B∩C)=A∩(B∩C) ′ =A∩(B ′ ∪C ′ )=(A∩B ′ )∪(A∩C ′ )=(A−B)∪(A−C)